2x^2-3x+9X=1

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Solution for 2x^2-3x+9X=1 equation: 


Simplifying
2x2 + -3x + 9X = 1

Reorder the terms:
9X + -3x + 2x2 = 1

Solving
9X + -3x + 2x2 = 1

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '3x' to each side of the equation.
9X + -3x + 3x + 2x2 = 1 + 3x

Combine like terms: -3x + 3x = 0
9X + 0 + 2x2 = 1 + 3x
9X + 2x2 = 1 + 3x

Add '-2x2' to each side of the equation.
9X + 2x2 + -2x2 = 1 + 3x + -2x2

Combine like terms: 2x2 + -2x2 = 0
9X + 0 = 1 + 3x + -2x2
9X = 1 + 3x + -2x2

Divide each side by '9'.
X = 0.1111111111 + 0.3333333333x + -0.2222222222x2

Simplifying
X = 0.1111111111 + 0.3333333333x + -0.2222222222x2

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